PNP E = 1.47v
PNP B = 0.8v
PNP C = 0v
Those voltages are not correct.
The emitter voltage is too high thats why you have 1.08v or so on pin 5.
What is the type of the transistor.??
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PNP E = 1.47v
PNP B = 0.8v
PNP C = 0v
I tried to move the components to opposite end of the breadboard, and all the voltage values were the same. I don't think the breadboard is to blame here.
Maybe I'll have to get a few 2N3906 from the store. I guess it's possible that I've burned them somehow during testing the circuit.
I posted my single opamp preamp and peak detector circuit in post #57 here: https://www.electro-tech-online.com...-problem-pictures-included.106176/#post868689
I mentioned in the text "Reduce the value of R9 a little or increase the value of R8 for more gain".hi agu,
The post #57 showing the peak detector has a gain of 1, no pre-amp shown, unless I am missing something.
Good morning everyone,
I think that the 1M pot might be a good idea just in case, or to have several different resistors to test what the gain should be. The mp3 output will be at fixed level(max volume), so there isn't room for adjustment there.
I will also need to hear the music at the same time from the mp3 source. I was planning to use just a simple 2€ headphone splitter, one end going to the amplifier and the other to the VU meter circuit. If this is somehow a bad idea, I could use suggestions for proper solution. Could there be signal attenuation?