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People say that this circuit works well. It stretches the pulse width to make the LED more visible.
Use it with the line level or headphone output of a CD or MP3 player. It might blow up with an output of a power amplifier unless an attenuator is added to the input.
The LED will light when the input has a peak voltage of 0.1V which is line level. It has a volume control to turn down the sensitivity.I'm very sorry, I know this is an old thread, but I just need to check something.. What can Vin be in your circuit?
People say that this circuit works well. It stretches the pulse width to make the LED more visible.
Use it with the line level or headphone output of a CD or MP3 player. It might blow up with an output of a power amplifier unless an attenuator is added to the input.
Somebody needs to design a current booster for the circuit to drive 16-20 LEDs.im going to be testing out haveing LEDS pulse with music.
But what about doing it with my car?
say about 16-20 leds in total. and making sure i dont blow out my leds.
how can i branch off from your circuit?
Yes.the Vin is the headphone positive and the circle under that is the headphone negative, correct?
The 10k resistor with arrow is how a volume control pot is drawn. The resistance track is connected between the input and ground to make an adjustable voltage divider for the signal. The arrow is the slider. Ground is 0V.But how come the 10k pot is connecting both and whats that black arrow right next to it?
it keeps the voltage from the little 9V battery from jumping up and down when the LEDs light.why is the 470uF capacitor bridging the battery?
Simply connect everything together that are shown connected together on the schematic.as i build this circuit i get more confused, how come the negative of the 9v battery connects to the LED then through the capacitor and resistor and back to the other end of the LED?