And I'm assuming I'd need to get that heatsink compound as well which I assume is similar to the Arctic Silver Compound used for transferring heat from a computer CPU to the heatsink.
Yes, you do need a heatsink if the load is on for any significant time. If you don't have a substantial metal chassis to mount it to then the heatsink you referenced should work fine. Heatsink compound is also recommended and it is the same as used with a computer CPU heatsink.
Yes, you do need a heatsink if the load is on for any significant time. If you don't have a substantial metal chassis to mount it to then the heatsink you referenced should work fine. Heatsink compound is also recommended and it is the same as used with a computer CPU heatsink.
Can't wait to get this in the mail and try it out. I'm hoping the input current limit for the cheap 25A SSR is similar to the expensive relay. I'll look around and see if I can find a datasheet for it.
I went to their site but the only information they provide on the SSR DC-DC is on this page which doesn't even list my device lol: FOTEK
I went with their 40A model instead of the 25A model since it was only $2.00 more , but I'm amazed at how much little info they provide for their products and the 1990s website design they have
But maybe the 7.5mA trigger current they have listed for the 5A model will apply for my 40A SSR?
It as well is stating a 7.5mA trigger current or below, so is it safe to assume that the DC input / DC output FOTEK 40A SSR will have the same requirements?
Also, if so, I'm curious to why it has it as: 7.5mA / 12v
It as well is stating a 7.5mA trigger current or below, so is it safe to assume that the DC input / DC output FOTEK 40A SSR will have the same requirements?
Also, if so, I'm curious to why it has it as: 7.5mA / 12v
Chances are they all have the same sensitivity since that is determined by the opto-coupler characteristics and not the output voltage or current.
The input is an LED and has a resistor (or some more elaborate circuit) to limit the input current. It is designed so the input will operate properly over a relatively wide voltage range. The 7.5mA / 12V just means that at 12V input voltage the input current will be 7.5mA. This current will vary with the input voltage.
Chances are they all have the same sensitivity since that is determined by the opto-coupler characteristics and not the output voltage or current.
The input is an LED and has a resistor (or some more elaborate circuit) to limit the input current. It is designed so the input will operate properly over a relatively wide voltage range. The 7.5mA / 12V just means that at 12V input voltage the input current will be 7.5mA. This current will vary with the input voltage.
Oh okay, so really when I get this thing in the mail, all I should have to do is hookup an output from my microprocessor to the input, and wire the motor connection plus the diode to the output portion of the SSR, and be done with it?
Since my uP only outputs 5v, and as you stated, the SSR will operate properly over a relatively wide voltage range, no external resistor on the input side should be needed? I think I've answered my own question, but just trying to confirm everything so I know exactly what to do when I get it, and if I've ordered everything I need
Obviously they ran out of the letter V so they used a W but forgot to chop part of the W off to make it a V. Very common practice in Taiwan. Because of their geographical location they constantly have problems stocking the letter V.
Actually I was surprised at the low cost of their SSRs. I hope they work well.
Since my uP only outputs 5v, and as you stated, the SSR will operate properly over a relatively wide voltage range, no external resistor on the input side should be needed? I think I've answered my own question, but just trying to confirm everything so I know exactly what to do when I get it, and if I've ordered everything I need
I would energize that SSR from a 5v power supply and measure its current draw before letting the uC assume control and possibly zapping its output pin. If it needs more than the uC can provide you'll still have work to do. 7.5ma @ 12v might be anything @ 5v. Nobody knows.
The SSR has a resistor in series with the internal LED. The resistor would be ~ (12V-1.7V)/7.5mA = 1.3K. So, at 5V the current will be ~(5-1.7V)/1.3K=2.5mA.
I would energize that SSR from a 5v power supply and measure its current draw before letting the uC assume control and possibly zapping its output pin.
Wait, first, what does uC mean lol (unit controller?)?
If it's just another name for the microprocessor, then how exactly will the microprocessor zap itself (or as you stated, it's output pin).
As far as being able to provide enough current, I know the 5v output can supply 7.5mA as the average LED draws about 20mA, and I can power an LED easily with an output pin from the microprocessor.
But yes, I will hook up a power supply to it and monitor how much current it's pulling at 5v.
It actually should be µC for microcontroller but sometimes the Greek letter mu (which is the micro prefix such as µF) is not available in the available font (although it is here) so u is commonly used in place of µ.