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If you have just a 9v battery with that 3Ω resistor across it's terminals then the voltage across the resistor = full voltage of the battery.
Just don't expect that battery to last long as 3Ω resistor would drain a fresh 9V in less than 15 minutes.
Also, a battery's voltage reduces as you draw more current from it.
voltage of the battery will be divided up among the resistances in the circuit?