To see how a speaker cone does vibrate on a circuit with a single ended power supply I designed the bellow to see if the cone does the negative vibration.
The strange thing is that there is a NEGATIVE swing at the load (RL) too??!
I am wondering how it does happen while there is no any split power supply or divider?
I thought maybe the collector of the transistor and the R1 are creating a voltage divider but soon I noticed the voltage divider is not able to case a negative voltage at RL because the other pin of the RL goes to the ground. I mean the RL is only able to swing between the positive and ground.
To see how a speaker cone does vibrate on a circuit with a single ended power supply I designed the bellow to see if the cone does the negative vibration.
The strange thing is that there is a NEGATIVE swing at the load (RL) too??!
I am wondering how it does happen while there is no any split power supply or divider?
I thought maybe the collector of the transistor and the R1 are creating a voltage divider but soon I noticed the voltage divider is not able to case a negative voltage at RL because the other pin of the RL goes to the ground. I mean the RL is only able to swing between the positive and ground.
Let's say there's no signal. The amplifier output at the capacitor input will be at a DC level of about 1/2 the positive supply voltage, and the output of the capacitor will be at 0V (through the speaker impedance to ground) since the capacitor does not conduct DC, only AC. Now we generate a negative going signal the causes the amp to drive the cap input in a negative direction from 1/2 the supply voltage to ground. This signal is coupled through the capacitor which drives the speaker in a negative direction from 0V to -1/2 the supply voltage, thus generating the negative signal you see at the speaker terminal.
Note the current flow [green] of the Load.
This charge/discharge of the 100uF, due to the sinewave voltage on the transistor collector, causes the current the the load to change direction. As it changes direction so does the polarity across the load.
Note the current flow [green] of the Load.
This charge/discharge of the 100uF, due to the sinewave voltage on the transistor collector, causes the current the the load to change direction. As it changes direction so does the polarity across the load.
At the bellow pic why there is a negative signal (bellow zero) for the signal source and the output load while there is a DC single ended power supply??
I seem to be too confused with these circuits.
Suppose a dual split power supply with load connected at its center pin (I.e The ground), The other pin of the load is variable between the positive pin of the power supply and e negative pin. Now we can tell that this load is swinging at the positive and the negative voltage. We can generate that state virtually but becuse one pins of the load at the first pic I posted is connected to the ground of the single ended power supply (I.e at the negative pin of the power supply while there is no any real or virtual ground) I am not able to see how that negative voltage is created? the capacitor at the first pic must reach to negative rates of the voltage (if we consider the negative pin of the power supply as the ground (i.e virtual center pin of a split power supply) of the load).
It's charged up to half the supply rail, so has 5V on the +ve end, and 0V on the negative (it's like a 5V battery).
When the collector of the transistor swings fully low, you're effectively connecting the +ve of this 'battery' to the 0V line, so it's -ve end is now -5V below 0V.
I have a question regarding the posters original attachment. The common emitter circuit has a base resistor attached to the supply rail. Now this will supply the base current but is this a good idea as the circuit is designed around a particular HFE and changing the transistor to another of the same type will not give the exact same HFE?
I have a question regarding the posters original attachment. The common emitter circuit has a base resistor attached to the supply rail. Now this will supply the base current but is this a good idea as the circuit is designed around a particular HFE and changing the transistor to another of the same type will not give the exact same HFE?