Ive got a mock up of the attached circuit on a breadboard...Ive substituted 2 LED's for the solenoids to see their operation. here is whats happening...I can remove the ground from the TIP41's emitter and the LED goes out. (got that part) I can add a ground to A, B, or off and the LED(s) go out. (easy enough) But why does the LED stay on when I remove the 12vdc from each half circuit? I would think that with the 12vdc gone, the base no longer gets any current and the ground between the emitter an collector would be open and the light would go out. Or is the ground going through D7 and around to ground? Is D7 even necessary? Could I remove it (D7) if I wanted to control the circuit by removing the 12vdc in this manner? Thanks for any info!!!