dasappettan
New Member
Hai friends
I want to make an antenna for my FM radio to receive a channel at 102.6 MHZ. Do you have any idea ?
I want to make an antenna for my FM radio to receive a channel at 102.6 MHZ. Do you have any idea ?
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dasappettan said:Hai friends
I want to make an antenna for my FM radio to receive a channel at 102.6 MHZ. Do you have any idea ?
dasappettan said:Hai friends
I want to make an antenna for my FM radio to receive a channel at 102.6 MHZ. Do you have any idea ?
V = velocity of the waveform (3x10.8ms-1)
F = frequency (Hz)
λ = length of one cycle of the 360.D waveform (m)
FM range 88 MHz to 108 MHz
Avg F = (108+88)/2 MHz
= 98 MHz
Applying V = F λ formula
(3 x 10.8) ms-1 = (98 x10.6) Hz x λ
300/98m = λ
3.0612m = λ
In λ/2 maximum voltage will present in the middle of the λ/2 conductor.
So the length of the dipole will be λ/2 = 1.5306m
Gaston said:you also need to consider the impedence of the input. for 300 ohm you can use 300 ohm twin pair wire to make the dipole. you can do the same for 75 ohm but you have to use a matching transformer.
Gayan Soyza said:There is no use making a FM antenna if there is no enough Signals coming from transmition stations, (due to obstacles,Weather, etc.....it can reduce the power of the wave form.)
I don’t know in which country you are...FM broadcasting Stations are not in a one particular place in most countries.(Not only FM, UHF & VHF as well). One station is in north & the other is in south………. So you need to rotate the antenna to focus each stations. This will not be a problem if you have All the broadcasting stations in a one place, so you need to Focus only to a one direction.
Simple steps to calculate the length of the dipole.
Note:the number after the decimal point represent superscript
If you need only for 102.6 MHz replace F in the formula & calculate The value of the dipole.Code:V = velocity of the waveform (3x10.8ms-1) F = frequency (Hz) λ = length of one cycle of the 360.D waveform (m) FM range 88 MHz to 108 MHz Avg F = (108+88)/2 MHz = 98 MHz Applying V = F λ formula (3 x 10.8) ms-1 = (98 x10.6) Hz x λ 300/98m = λ 3.0612m = λ In λ/2 maximum voltage will present in the middle of the λ/2 conductor. So the length of the dipole will be λ/2 = 1.5306m
That amplifer only goes to ~70MHz. You need an amplifier that works at 88 to 108MHz....I am also considering circuit at "...?