Yes, I know that. The coil I was using in the simulation last night has 2 ohms of resistance. That really helped to reduce the current through the diode(s). Keep in mind, I did not design that circuit, I am only trying to analyze it.
Even at that high value, the transistor still burns up. But it's naive to think the coil would protect the transistor anyway. Trying to get a high enough value works against other circuit goals.
That is probably true. I will leave it to MrAl to confirm it.
Absolutely true. No confirmation required.
EDIT: The other "diode" is an arrow indicating the dirction of current. (Yeah, yeah I know the direction of current is already implied, but that's what it is nontheless)
Yes, I already said previously that transistor saturation is what turns the diode(s) off.
Then there should be no reason to ask why I don't consider the diode. That is the answer.
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