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I don't understand -
12v x 1A = 12W
or
50W/12V = 4.1A
12Vac = 12v x 1.41* = 16.8Vdc
* (RMS)
13.8V is ideal for charging lead acid batteries, with the two diode drop from 16v it will be ok.
If you're using an inverter, that should have a battery low shut-down to stop the battery discharging too much, but it's also an idea to us a wind charger controller that can dump energy into a load when it's very windy or when the battery is fully charged.
I have a simple FET voltage clamp that dumps load into a high power resistor in a bucket of water when the voltage goes over 14v.
The 50W after the inverter, that makes more sense.