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The Vout is going to be a DC level proportional to the AC excited Wheatstone Bridge output. I think you need to do some reading and understand what an ADC is and how it works. The DC level applied to the ADC is very much an analog signal. The LF351 operational amplifier is a pretty old chip, today there are much better solutions, including a wide range of instrumentation amplifiers better suited for your drawing. Your drawing serves more as an example than a practical application circuit. Using a uC (micro-controller) with an ADC (Analog to Digital Converter) you write code for the ADC to convert a DC level input to some engineering unit.
Ron
Let's try using an example. I have a whetstone bridge or any sensor circuit. My sensor measures 0 to 10 PSI (Pounds per Square Inch) or pressure. After signal processing and signal conditioning let's say my pressure transducer (pressure sensor) is a 0 to 500 PSI sensor and outputs 0 to 10 volts. Now 0 to 500 PSI is represented by 0 to 10 volts.Could you share some information about ADC to me ? I researched a lot but I didn't still understand relationship between DC level and AC
An ADC converts an input voltage (which may be a fixed or varying DC level or an alternating AC signal) into a digital number represented by a set (e.g. 8 or 10) of binary bits.
unless you don't want to explain us all what is electric charge -- it is something understanding the basic robust time scale bulk statistical behaviour and some energy relations with known physics . . . of the charged particles - - besides i don't follow your ADC bits quite well the [ s ] tag enables error indication [edit] button enables . . . any second opinionsunderstanding the basic principals of electronics
? the energy changes in AC versus in it's rectified (? and scaled) DC characteristic levelunderstand relationship between DC level and AC
as a programmer - finding the bugs is mostly what i have been doing in the past . . .There is no analog signal . It is DC , so How can I convert ADC for output of Vo ?
I thought in my case my 1K was actually 1024 quantization levels? 0 to 1,000 would be 1024 steps. I tried to use a simple explanation based on the original post. Since my attempt was not very good maybe you should explain it so the original poster can understand.not that passing a naming error would be something over critical but that it may take quite a while for a novice to figure out that your 1kb actually stands for 1k quantization levels
using "bits" insted of "steps" or "x-levels" does not make it "not very good" you're overreacting -- i usually read my post before/+after publishing -- scanning the logic/context and syntax errors -- fix ASAPSince my attempt was not very good