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Hey qtommer, check this out: Exploring the s-Plane
Play with the interactive s-plane. It's pretty cool
A diode clipper clips the signal to limit the amplitude. A light bulb (it changes its resistance with the amplitude of the signal across it) or a FET amplitude stabilizer circuit do not clip the signal.
Does this mean that the purpose of amplitude stabilization is NOT to ensure that the sine wave edges are distorted (clipped) but it IS to ensure that a sine wave with constant amplitude is generated right from the start without waiting for it to have to grow?
Thank you all so much
thank you so much Brownout and eric=)
ive a better understanding now thank you so much...
now im simulating the wien bridge without amplitude stabilization (ive removed the diodes).. when i set the gain to exactly 3, i know that there will be no oscillatons and there will be a flat line at 0V.
however, when i zoomed into the flat line i noticed a rather odd repetitive waveform (as attached) is there any reason why the shape is so?
thank you all once again=)
It seems that you don't know how to properly "set" the simulation.
Here you have two examples:
You don't want rail-to-rail oscillations. You're getting a good sine wave because you're intentionally not going to the rail.
In this case, when the signal reaches a cetain value, the diodes short out R6, and now the gain is:
1 + (15K + 0/10K) = 2.5. that will stop the signal from growing. In that way, the tops of the signal aren't clipped by hitting the power rail.
Quote:
Originally Posted by qtommer View Post
therefore is it correct to say that if the loop gain is less than 1, it would be on the left side of the s plane and becomes a stable op amp thus resulting in attenuations in the circuit?
The position of the roots on the left side affect the response of the amplifier. You can have a damped system or undamped, depending on exactly where the poles lie. However, you're right that the system would be stable