Roff Well-Known Member Jun 30, 2006 #41 km said: Unfortunately that doesn't work. This time, i followed the resistor values in the application note. i just exchange the R18 & R19 values. I got the Triangle! Can anyone tell me what is happenning? Click to expand... If the IA is working correctly, the triangle output should be symmetrical around zero volts. Is it?
km said: Unfortunately that doesn't work. This time, i followed the resistor values in the application note. i just exchange the R18 & R19 values. I got the Triangle! Can anyone tell me what is happenning? Click to expand... If the IA is working correctly, the triangle output should be symmetrical around zero volts. Is it?
K km New Member Jun 30, 2006 #42 Ron H said: If the IA is working correctly, the triangle output should be symmetrical around zero volts. Is it? Click to expand... You mean the output was incorrect?
Ron H said: If the IA is working correctly, the triangle output should be symmetrical around zero volts. Is it? Click to expand... You mean the output was incorrect?
Roff Well-Known Member Jun 30, 2006 #43 km said: You mean the output was incorrect? Click to expand... I don't know. I can't tell from your scope photo what the voltage levels of the triangle are.
km said: You mean the output was incorrect? Click to expand... I don't know. I can't tell from your scope photo what the voltage levels of the triangle are.
K km New Member Jul 14, 2006 #44 Hi Ron, May i ask why at higher frequencies, the waveforms will be distorted? How does the IA works to get the triangle wave? Is it differentially amplifying the capacitor waveforms? Attachments distortion.JPG 81 KB · Views: 121
Hi Ron, May i ask why at higher frequencies, the waveforms will be distorted? How does the IA works to get the triangle wave? Is it differentially amplifying the capacitor waveforms?