thanks for all the input here!
The 5 volt battery is actually a 9 volt with a regulator. I am now thinking this is also a bad idea considering it's just wasting the rest as heat.
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Let me get back to the rest of the responses after I ask this question.
take any battery Xvolts and put a resistor on it Yohms
The resistor itself will expend so much as heat but what about the rest?
what happens to the rest of the energy?
lets also assume it's just a closed circuit, simple as you can get.
what i am trying to understand here is this.
lets say
1) take a simple circuit, a single component of that circuit uses 500microamps
2) take that same circuit and change the component , now it used 700microamps
What i dont understand is if this simple configuration was able to supply both requirements, is there an amount that is being wasted?
there is a 200 unit difference between 500 and 700, does this mean that the circuit was supplying more than both but the component was burning of , say, 500 but wasting the rest somehow?
i really hope that makes sense.....