power op amp

[Juggler73]

hi

this is not my design i got it from another forum i just wanted someone to have a look over this and make sure im doing this right or wrong and give me some help in doing it right
thanks

 

[Wade Hassler]

What does it do? It doesn't seem to have an input.
More info, please

 

[Hero999]

It looks like an odd solution.

It contains a couple of redundant components:

R4 can be replaced with a short circuit.

R3 can be replaced with an open circuit.

 

[MikeMl]

Isn't it supposed to be an active Power Supply splitter? i.e. it makes +9.5V and -9.5V from a 19V input.

How much current are you planning to draw off the two rails?

 

[Juggler73]

it will have a adapter plug on the case connected to the + and - on the board

9v on each rail

its to power my headphone amp from a 19v adapter, replacing the 2 9v batteries

all i need to know really is that ive planned out the stripboard properly from the diagram

thanks

 

[Hero999]

It uses a high power op-amp which is certainly enough to power a pair of headphones.
https://www.electro-tech-online.com/custompdfs/2010/04/L22FL272.pdf

As I said above, remove R3 and R4. I checked the datasheet and it seems like it'll be stable for unity gain so it will be fine.

EDIT:

You've asked this question before haven't you?

I fogotten whether it was here or on another forum.

 

[Juggler73]

all i need to know really is that if I'VE planned out the stripboard properly from the diagram

thanks

 

[MRCecil]

No, it does not appear to be laid out correctly. Vcc is going directly to pin 7. The voltage divider R1 & R2 is not configured correctly. I second Hero's suggestion that you eliminate R3 & R4 and place a wire jumper in place of R4. Correct the issues, then I would recommend testing before you put it to use.

To test the output, I suggest you take the two removed resistors and place one from the 19V rail to pin 1 and the other from the ground rail to pin 1 (a test load). Then measure the voltage across each, which should be ~9.5V for both. Then replace the 10K with another 1K and repeat the measurement, which should also be ~9.5V

Good luck.