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Drain to source, antiparallel: no change; the load is resistive.Schottky or high speed diode anti-parallel to each MOSFET.
What are you feeding the opto-output too? It might be easiest just to debounce the signal with hardware or code rather than dealing with the spike because I'm not sure where that's coming from, but you had something similar with 2V in an earlier incarnation.Forward voltage drop on rectifier diodes: 0.7V.
The reason for the rectifier is to serve as input to an optocoupler. The H-bridge serves to send a square wave ac signal to sensor probes. When open (no liquid), the full voltage is forwarded to the rectifier, subsequently to the optocoupler. When closed (ie sensor probes shorted, liquid present) no voltage is present and optocoupler not activated.
When the optocoupler is not activated it serves to send signal to controller to activate whatever. There is no issue with the spikes when the optocoupler is not activated, so not to bad in that respect, but I would like the signal to be clean too when the optocoupler is activated, if only not to perturb the anxillary components.
Here is the preliminary schematic. Part of interest is upper right.What are you feeding the opto-output too? It might be easiest just to debounce the signal with hardware or code rather than dealing with the spike because I'm not sure where that's coming from, but you had something similar with 2V in an earlier incarnation.
Maybe just throw a clamp diode across the output of the rectifier just to make sure the spike isn't damaging and then debounce the thing to deal with the blip in the signal. A schottky should clamp the undershoot to -0.3 to -0.5V.Yes, has been checked: it actually is more of a problem of microsecond delay between shutting down one side and starting up the other side.
It is a latch, but this was pointed out previously (in another thread) and he's added pull-up resistors to the drains of the two lower MOSFETs which solved the issue.First, convince me that this is even an H-bridge. After the first edge from the 555, it never changes state again. It looks more like a latch to me.
View attachment 111649
Then why the hell didn't he just add to the existing thread instead of starting a new one?It is a latch, but this was pointed out previously (in another thread) and he's added pull-up resistors to the drains of the two lower MOSFETs which solved the issue.
Same circuit but the thread was started for a specific issue in that circuit and once that was solved he didn't want to muddy things up by mixing everything into the same thread.The why the hell didn't he just add to the existing thread instead of starting a new one?
How could I be more confused?Same circuit but the thread was started for a specific issue in that circuit and once that was solved he didn't want to muddy things up by mixing everything into the same thread.
Measured across the load.First, convince me that this is even an H-bridge. After the first edge from the 555, it never changes state again. It looks more like a latch to me.
View attachment 111649
Clamp diode: when no voltage is present, no spikes. When voltage is present, the spikes are to ground.Maybe just throw a clamp diode across the output of the rectifier just to make sure the spike isn't damaging and then debounce the thing to deal with the blip in the signal. A schottky should clamp the undershoot to -0.3 to -0.5V.
Where is the scope probe ground clip? You have a floating load. If the scope chassis is grounded to the AC line, then the only way you could read the voltage across the filter capacitor is with a true-differential measurement....What puzzles me is that a cap across the rectifier output cannot smoothen these downward spikes.
Interesting.Where is the scope probe ground clip? You have a floating load. If the scope chassis is grounded to the AC line, then the only way you could read the voltage across the filter capacitor is with a true-differential measurement.