I got to make this school project.
This is how should it work:
I need to make circuit that will on every fifth impulse (f=1Hz) that I bring on entrance turn off LED which is located at output. When sixth impulse comes to entrance it must turn on LED and repeat that all over again.
Here is what i think how should i solve this problem:
I will use IC NE555 for generation impulses of 1Hz. Then i will bring that signal on Counter and after counter i will put divider. I will connect LED at outputs of divider so when 5th impulse comes at entrance it will turn LED off and when 6th impulse comes at entrance it will turn LED on again.
So its: 555->Counter->Divider->LED
I got to make this school project.
This is how should it work:
I need to make circuit that will on every fifth impulse (f=1Hz) that I bring on entrance turn off LED which is located at output. When sixth impulse comes to entrance it must turn on LED and repeat that all over again.
Here is what i think how should i solve this problem:
I will use IC NE555 for generation impulses of 1Hz. Then i will bring that signal on Counter and after counter i will put divider. I will connect LED at outputs of divider so when 5th impulse comes at entrance it will turn LED off and when 6th impulse comes at entrance it will turn LED on again.
So its: 555->Counter->Divider->LED
Configure the 555 as an astable multivibrator for your 1 Hz clock as you mention. Then use a 4017 decade counter/divider. Place an LED on Q4 and Q9 of the 4017. Use diodes (1N914) to connect the LED. Cathode side to the LED. Does that make sense? Check out the 4017 data sheet.
<EDIT> Beaten by Eric. with a better explenation. </EDIT>
10 LED CHASER Here's an interesting circuit that creates a clock pulse for a 4017 from a flashing LED. The flashing LED takes almost no current between flashes and thus the clock line is low via the 1k to 22k resistor. When the LED flashes, the voltage on the clock line is about 2v -3v below the rail voltage (depending on the value of the resistor) and this is sufficient for the chip to see a HIGH. Put the LED on the 6th output and return the 7th output to the reset line. The flashing LED will let you know the number of pulses and the LED will illuminate on the 6th pulse. (circuit designed on 9-10-2010)
I think i cant use 4017.
It must be all in TTL group and 4017 is CMOS.
For counter i will use 7493 so i need only divider which will have LED at output right ?
Ill try to make this with
555->7493-> use logic gates (and, or, xor) to use that BCD code and make circuit that will give me 0 at output when counter count fifth impulse
My mistake... i can use 4017
Why put LED and resistor on the 6th output ?
I thought i need to put it on 5th (Q4) and reset pin on 6th (Q5) output.
So it will turn off when 5th impulse come at entrance right ?
EDIT: nwm i just saw it in datasheet It has to be LED on 6th and RST on 7th output thx
My mistake... i can use 4017
Why put LED and resistor on the 6th output ?
I thought i need to put it on 5th (Q4) and reset pin on 6th (Q5) output.
So it will turn off when 5th impulse come at entrance right ?
EDIT: nwm i just saw it in datasheet It has to be LED on 6th and RST on 7th output thx