how i can make dicoder?

[diod]

hi
i have 4 dicoder that each dicoder is 4 to 16.i want make one dicoder with this 4 dicoders that it would be 6 to 64.then how i can make it?

 

[Dragon Tamer]

We discussed this in chat, you need some way of decoding the extra data lines that are not being used by the decoders, to enable and disable the 4-16 decoders that you already have. This will need a 2 to 4 decoder that you can build yourself, as I showed you earlier, or you can try to get an IC that already has the decoder function built in. You can try looking into the 74139 as your 2-4 decoder, here is the data sheet for it: https://www.electro-tech-online.com/custompdfs/2011/12/74HC_HCT139_CNV.pdf

If you are looking for another way of doing what you want to, there isn't one unless you want to make the entire decoder from scratch.

 

[diod]

how i can connect 4 dicoder to what or which gate or divice to make final (dicoder 6-64)?i khow what you mean.i can understand how i can use dicoder 2 to 4.t it would be 6 to 64?and could you explain how it work?i am just student.i havent more information.i need your help.
i am not stupic i cant explain my guestion right.and my english isnt good
.thanks alot










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[diod]

i am waiting for your help,could you send schematic again.if it pussible.

 

[Mr RB]

The 6 to 64 decoder will only have one output on at one time.

Are you going to step between all the 64 outputs in a sequence (1 -> 64)? If you are, then you could use cascaded 4017 ICs, the circuit will be much simpler.

 

[Dragon Tamer]

The 2-4 decoder will always have an output active, this active output will drive the enable pin on the 4-16 decoders. Depending on the IC that you are using for the 4-16 decoder, the enable pin will be either active high or active low. When the enable pin is not active, the 4-16 decoder will not decode the signal at all, and all outputs will be at their inactive state regardless of the input.

 

[diod]

thanks alot.i can understand