So in this case, you need four individual devices, each switching one bulb. The choice of the device is yours but in the end, it must satisfy the following two conditions :
1) On one side, it has to be rated for the AC requirements you have : 120VAC and at least I = P/V = 208.33mA AC. To be safe, I would look for : 120 VAC, 1A
2) On the other side, you have to check the DC voltage and current required to turn on the device and see if your MCU port can provide that :
a) Check the device current rating (Idevice) :
- If the MCU port cannot source that much current, you will need to use a transistor and go to step c)
- If the MCU port can source that much current, you are not sure yet if a transistor is required or not so go to step b)
b) Check the MCU output voltage for logic high (VOH) at the given current* and compare against the device voltage rating (Vdevice).
- If the MCU port voltage at the given current is too low, you will need to use a transsitor and go to step c)
- If the MCU port voltage at the given current is too high, you will need to use a limiting resistor R = (VOH - Vdevice) / Idevice. You're done.
c) If a transistor is required, compare the device voltage rating (Vdevice) against 5VDC and the transistor voltage drop (Vgs or Vce) at given current (Idevice) :
- If 5VDC - Vtransistor is too high, you will need to use a limiting resistor R = (5VDC - Vtransistor - Vdevice) / Idevice. You're done.
So when you've chosen your device, let us know if you want us to validate the choice or if you need a circuit example.
* A 5V MCU will output a logic "1" to a port with a high voltage close to 5V. But the more current you ask of the port, the lower the voltage will actually become. For example, at 20mA, the voltage could go as low as 2.5V or so.