Hi.... mbarazeen ..
I have deeply look at your circuit but I am sorry...
I think you need to reconsider the logic.
As it stands as per your circuit - the motor will only run while the 3-hour timer is not running
i.e. while pin 12 of the 4060 is being held high.
The moment the 3-hour timer starts to run -
pin 12 (A) will be taken low - and the relay will de-energize.
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Friend what I want I have told you previously .. and gaven lots of information about my project...
Here the 3hr timer is the total time in which all the operation will perform like turning on/off motor according to the logic's..
but the problem is not in logic... logic is good working...
Here The total time period will be 3hr and after 3hr the motor pump will stay off... untill the 3hr timer starts...
So the all the process of turning motor on/off will be done in between 3 hr.. because after 3hr motor will remain off.... untill the 3hr timer starts again..
But friend I have used my mind and created a circuit diagram which I have attached in my attachment.. and the details I haved gaven below...
so please have a look...
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First.....
AS THE 3HR TIMER WILL BE RUNNING IT'S PIN 12 & 13 WILL BE LOW AND OUTPUT PIN 11 WILL BE HIGH..
AND OUTPUT PIN 11 WILL WILL ALSO TAKE PIN 6 OF GATE2 & PIN 8 & 9 OF GATE 3 HIGH...
SO THE OUTPUT OF GATE 3(PIN 10) WILL BE LOW AND TIMER WILL BE RUNNING...
TAKING IT FIRST ROUND OF 10 MINUTES ON ....
IT WILL TAKE PIN 1 & 2 OF GATE 1 HIGH AND THEREFORE THE OUTPUT AT PIN 3 WILL BE LOW..
PIN 3 WILL ALSO TAKE PIN 5 OF GATE 2 LOW..
THEN..
NOW WHAT WILL BE THE OUTPUT OF GATE 2(WHICH IS USED TO TURN MOTOR ON/OFF)..
TO DRIVE MOTOR WE WANT 5 & 6 OF GATE 2 LOW, SO THAT OUTPUT PIN 4 BECOMES HIGH TO DRIVE MOTOR..OR
0 + 0 = 1
1 + 0 = 1
0 + 1 = 1
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SO WHAT RESULT WE GOT HERE...
AS 3HR TIMER IS RUNNING SO PIN 11 IS HIGH WHICH ALSO TAKES PIN 6 HIGH.
AS ANOTHER TIMER IS TAKING IT'S FIRST 10 MINUTES ROUND , SO PIN 3 IS LOW..
1 + 0 = 1
SO THE INPUT OF GATE2 PIN 5 & 6 BECOMES LOW THE OUTPUT OF GATE2(PIN 4) IS HIGH AND WILL TURN ON THE MOTOR.
NEXT.....
3 HR TIMER IS RUNNING....
TIMER 2 BECOMES OFF AFTER 10 MINUTES AND IT WILL STAY OFF FOR 30 MINUTES .. AND WE WANT TO TURN OFF
THE MOTOR... SO WE WANT..
1 + 1 = 0.
SO WHAT RESULT WE GOT HERE...
AS 3HR TIMER IS RUNNING SO PIN 11 IS HIGH WHICH ALSO TAKES PIN 6 HIGH.
AS TIMER 2 WILL REMAIN OFF TILL 30 MINUTES , SO PIN 1 & 2 IS LOW AND PIN 3 IS HIGH..
1 + 1 = 0
SO THE INPUT OF GATE2 PIN 5 & 6 BECOMES HIGH AND OUTPUT OF GATE2(PIN 4) IS LOW AND IT WILL TURN OFF THE MOTOR.
LAST....
3 HR TIME IS OVER AND NOW 3HR TIMER IS OFF...
WE WANT TO TURN OFF THE MOTOR...
SO WE WILL DO THIS BY PAUSING THE TIMER2.
AS 3HR TIMER IS OFF , ITS 12 & 13 PIN WILL BE HIGH AND OUTPUT PIN 11 WILL BE LOW..
GATE3 INPUT PIN 8 & 9 TO BECOME LOW.. AS IT BECOMES LOW THE OUPUT PIN 10 BECOMES HIGH AND IT WILL
TAKE PIN 12 & 13 OF CONTROL CIRCUIT TO HIGH AND THE OUTPUT PIN 11 OF CONTROL CIRCUIT BECOMES LOW..
WHICH WILL TAKE PIN 1 OF TIMER2 LOW.. SO THE TIMER2 WILL PAUSE..
AND THE MOTOR PUMP WILL BE OFF..
AND THIS REPEATS...
AS THE 3HR TIMER STARTS TO RUN...
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Thanks for co-operation....
Thanks in advance..
Yusuf..