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GETTING STEADY

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Because of the current cource, which cannot be open circuited, I drafted two cases for an initial condition.

The diffficulties only occurs when t=0.
 

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THANKYOU LOTS AND LOADS!!![/color]

I really hope this is the end of my doubts.It is in this section atleast :)wink:)heheh
It feels good to know there are people out there who really help!

Best regards
niga
 
eblc1388 said:
Because of the current cource, which cannot be open circuited, I drafted two cases for an initial condition.

The diffficulties only occurs when t=0.

There is no need to open or short the current source.

The current source is a step function that goes from 0 to I at t = 0.

I(t) = I u(t)

This is clearer if you solve the problem using Laplace Transforms. See attachment.

Len
 

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Hi len,

U have gone through a lot of trouble drafting all this for me.I am sure many others also found your informations useful.Thankyou so much again.

Sincere regards-niga
 
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