T twiart New Member Jan 31, 2009 #1 Hello guys,do you know how to generate this table? https://i44.tinypic.com/4tok05.jpg How to calculate actual frequency for each note in different octave,and how do we know the divider for each note,are they fixed? Thanks in advance.
Hello guys,do you know how to generate this table? https://i44.tinypic.com/4tok05.jpg How to calculate actual frequency for each note in different octave,and how do we know the divider for each note,are they fixed? Thanks in advance.
Nigel Goodwin Super Moderator Most Helpful Member Jan 31, 2009 #2 Each octave is twice the previous one, it's a simple mathematical progression.
T twiart New Member Jan 31, 2009 #3 Nigel Goodwin said: Each octave is twice the previous one, it's a simple mathematical progression. Click to expand... What about the divider value for each note?
Nigel Goodwin said: Each octave is twice the previous one, it's a simple mathematical progression. Click to expand... What about the divider value for each note?
K KMoffett Well-Known Member Jan 31, 2009 #5 twiart said: What about the divider value for each note? Click to expand... That was the principal for the long obsolete (think I still have one) Mostek MK50240 a top octave generator. One IC generated all the notes in the top octave, and dividers were used to produced all the notes in the lower octaves. Ken
twiart said: What about the divider value for each note? Click to expand... That was the principal for the long obsolete (think I still have one) Mostek MK50240 a top octave generator. One IC generated all the notes in the top octave, and dividers were used to produced all the notes in the lower octaves. Ken
Hero999 Banned Jan 31, 2009 #6 It's easy to build an oscillator using a Schmitt trigger. You could use two hex Schmitt trigger ICs to get 12 different frequencies and divide them down using a divider. I think an MCU is a better option but as this a college project it'll probably be forbidden.
It's easy to build an oscillator using a Schmitt trigger. You could use two hex Schmitt trigger ICs to get 12 different frequencies and divide them down using a divider. I think an MCU is a better option but as this a college project it'll probably be forbidden.
F flat5 Member Jan 31, 2009 #7 In the equal tempered scale the notes are separated by the 12th root of two. (1.059463094) So, A being 440, A# is 440 X 1.059463094 = 466.1637615 Multiply A# by the magic number and you get B. Keep going 12 times and you get the octave of A - 880 On a calculator, take the log of 2, divide it by 12 and take the anti log to get the magic number. Last edited: Jan 31, 2009
In the equal tempered scale the notes are separated by the 12th root of two. (1.059463094) So, A being 440, A# is 440 X 1.059463094 = 466.1637615 Multiply A# by the magic number and you get B. Keep going 12 times and you get the octave of A - 880 On a calculator, take the log of 2, divide it by 12 and take the anti log to get the magic number.