Electromagnetic Theory

Status
Not open for further replies.

The final steady state current for any open circuited coil is zero. All the rest of the information is spurious. In practice something nasty happens when you open the switch (arcing typically), but ultimately the current is interrupted and drops to zero.
 
The Question is not verry clear

there is a AC voltage suplied so the current would also be alternating

that means there is no steady current only an changing one and out of phase of the voltage

could it be that they ask if the curent is 692 mA after 3.2 ms

you have to calculate the inductance from there you have to calculate the coil resistance and then you have to calculate the staedy current in case the field breakes down deu to the resitance of the coil

is it not that if the power is switched off the frequency will be 0Hz and the field can be seen as a in/decreasing dc voltage and with the risistance of the coil you will have a current (altought i don't think it's a steady one)

Just guesing

Robert-Jan
 
Thanks guys.
All you have said makes sense.
the university came back to me stating that this question is incorrect, and they are reviewing all questions now to short-circuit such problems.
Apparently I must use the formula i(t) = I(max) (1-e (-t/T)) to work out the final steady current if it could exist, etc.
This is a bit silly since the whole thing is wrong, but I'll do for now.
It must be one of those imaginative conditions.
Go well all
 

That's a big core! What is that...2.4"? I use Amidon all the time.
 
Status
Not open for further replies.
Cookies are required to use this site. You must accept them to continue using the site. Learn more…