Dr_Doggy
Well-Known Member
so I got some salt water, when i apply it to a supply i get current based on volts and resistance, first for simplicity lets assume that the salt to water ratio won't change throughout the process.
As i understand there is a minimum of 2v(or so) required to start the electrolysis process, so when at the ideal voltage i can calculate the current based on Vapplied /Resistance of load = Icurrent at most effective output.
but when i go under that voltage the load resistance doesnt change so I can still calculate amps.
however what if i go over that voltage, naturally current increases, output increases, but efficiency drops due to heat losses(i think)
so my questions are:
when im under ideal voltage is the current i measure on ammeter the heat loss?
when im at ideal can i measure: current on ammeter = ((heat lost @(ideal -0.01degree) ) + output electrolysis)?
will the reaction reflect in the current of the circuit?
I guess I am wondering if there is a way to identify the ideal voltage or efficiency of my reaction (since it may change with shape/volume of container) without measuring the output gasses, and instead only measuring using the current and maybe temperature (or similar)?
Maybe im confused: when i measure current am i measuring the energy that got converted to heat and electrolysis output?
or
is there a way to control a lm317 or similar to ensure that Im always at ideal reaction voltage regardless of my volume & surface area?
As i understand there is a minimum of 2v(or so) required to start the electrolysis process, so when at the ideal voltage i can calculate the current based on Vapplied /Resistance of load = Icurrent at most effective output.
but when i go under that voltage the load resistance doesnt change so I can still calculate amps.
however what if i go over that voltage, naturally current increases, output increases, but efficiency drops due to heat losses(i think)
so my questions are:
when im under ideal voltage is the current i measure on ammeter the heat loss?
when im at ideal can i measure: current on ammeter = ((heat lost @(ideal -0.01degree) ) + output electrolysis)?
will the reaction reflect in the current of the circuit?
I guess I am wondering if there is a way to identify the ideal voltage or efficiency of my reaction (since it may change with shape/volume of container) without measuring the output gasses, and instead only measuring using the current and maybe temperature (or similar)?
Maybe im confused: when i measure current am i measuring the energy that got converted to heat and electrolysis output?
or
is there a way to control a lm317 or similar to ensure that Im always at ideal reaction voltage regardless of my volume & surface area?