I've got a PIC18F458 microprocessor feeding an 8 bit number into a digital to analog converter. The analog converter is to spit out -10V for 00000000 and +10V for 11111111, and everything in between. (-10=>0=>+10V)
I'm using a DAC800LCN digital to analog converter chip.
First question:
The data sheet for the chip is located here:
https://www.electro-tech-online.com/custompdfs/2007/10/DAC0800.pdf
On page 3 it has two different types of casing packages. The chip I has the text: JM024AD, DAC0800LCN, DAC-08EP on it, which chip is it, the one on the left or the one on the right? I suspect its the one on the left as the chip has that DOT which indicates where pin 1 is as shown on the figure on the left.
Second question:
I've wired this chip up like this:
**broken link removed**
In the typical application figure 8 labelled "Symmetrical offset binary operation" which is the mode of operation I'm after. If I wire up Vref(+) to +10V, Vref(-) to -10V and the rails at +/-15V, as shown in my drawing, do I need that op amp out the front? Will Io spit out -10 to +10V depending on the binary input? (00000000=-10V, 11111111=+10V).
If thats the case, if you look at the typical application noted on page 1, figure 1, why have they got the resistors on the output to what appears to be Vref(+). Do I need these resistors? ie. is the chip open collector? or can I just take the voltage (+/-10V, 20vp-p) out of Io without any external resistances in place.
Your help is appreciated.
Thank you
I'm using a DAC800LCN digital to analog converter chip.
First question:
The data sheet for the chip is located here:
https://www.electro-tech-online.com/custompdfs/2007/10/DAC0800.pdf
On page 3 it has two different types of casing packages. The chip I has the text: JM024AD, DAC0800LCN, DAC-08EP on it, which chip is it, the one on the left or the one on the right? I suspect its the one on the left as the chip has that DOT which indicates where pin 1 is as shown on the figure on the left.
Second question:
I've wired this chip up like this:
**broken link removed**
In the typical application figure 8 labelled "Symmetrical offset binary operation" which is the mode of operation I'm after. If I wire up Vref(+) to +10V, Vref(-) to -10V and the rails at +/-15V, as shown in my drawing, do I need that op amp out the front? Will Io spit out -10 to +10V depending on the binary input? (00000000=-10V, 11111111=+10V).
If thats the case, if you look at the typical application noted on page 1, figure 1, why have they got the resistors on the output to what appears to be Vref(+). Do I need these resistors? ie. is the chip open collector? or can I just take the voltage (+/-10V, 20vp-p) out of Io without any external resistances in place.
Your help is appreciated.
Thank you