I designed this flashlight after playing with my first project and learned a few things about output, viewing angle, etc. Still learning though, so heres my idea to get some feedback. :?
Power Supply
9.6V 900 mAh Ni-Cd battery pack.
Individual LED Info
Style= 5mm 16000 mcd super pure white :twisted:
Voltage Drop= 3.4 volts
Current= 25 mA
Viewing Angle= 15 degrees
Project Info
10 banks of 2 LED's, with one 115ohm 1 watt resistor per bank.
The 2 LED's are wired in series and the banks are wired in parallel.
All mounted into a 6 volt flashlight housing.
-----------------------------------
R = V/I
R = (9.6 - 2*3.4) / 0.025 =
= 2.8 / .025
= 115 ohm resistor
-----------------------------------
I = V / R
I = 2.8 / 115 ohms
I = .024 or 24mA
----------------------------------
Total Current = 10 * 24 = 240 mA
----------------------------------
Do my calculations seem accurate? I know the battery pack voltage varies, as I have seen around 11V from it. Should I do the calculations using the higher voltage for the resistors?
R = (11 - 6.8) / .025
= 4.2 / .025
= 168 ohms
If I leave in the 115ohm resistors each LED will be drawing approx 37mA and using 4.2V. Still within the safe zone??? (probably not, eh) :shock:
Any thoughts would be appreciated.
I have drawn up a schematic, can post it if you want.
[/u]
Power Supply
9.6V 900 mAh Ni-Cd battery pack.
Individual LED Info
Style= 5mm 16000 mcd super pure white :twisted:
Voltage Drop= 3.4 volts
Current= 25 mA
Viewing Angle= 15 degrees
Project Info
10 banks of 2 LED's, with one 115ohm 1 watt resistor per bank.
The 2 LED's are wired in series and the banks are wired in parallel.
All mounted into a 6 volt flashlight housing.
-----------------------------------
R = V/I
R = (9.6 - 2*3.4) / 0.025 =
= 2.8 / .025
= 115 ohm resistor
-----------------------------------
I = V / R
I = 2.8 / 115 ohms
I = .024 or 24mA
----------------------------------
Total Current = 10 * 24 = 240 mA
----------------------------------
Do my calculations seem accurate? I know the battery pack voltage varies, as I have seen around 11V from it. Should I do the calculations using the higher voltage for the resistors?
R = (11 - 6.8) / .025
= 4.2 / .025
= 168 ohms
If I leave in the 115ohm resistors each LED will be drawing approx 37mA and using 4.2V. Still within the safe zone??? (probably not, eh) :shock:
Any thoughts would be appreciated.
I have drawn up a schematic, can post it if you want.
[/u]