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Capacitor in series AND parallel

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Mikebits

Well-Known Member

crutschow

Well-Known Member
Most Helpful Member
You calculate the value for C2 and C3 in parallel. Then use the calculated value in series with C1.
 

Grossel

Well-Known Member
This gives 66 2/3 µF :D
 

crutschow

Well-Known Member
Most Helpful Member
Aw, you told him the answer.
 

Grossel

Well-Known Member
Aw, you told him the answer.
Yes, but he still have to calculate it and find out how.

Or no actually. I cannot say providing any number is really the answer. A real answer would being to tell the whole process (formula) to get to that number.
 

Voltz

New Member
That's what I thought, (calculate the capacitance value of the two in parallel and then use that with the one in series)
Ran that through the calculator and I got 66.6u
 

Sceadwian

Banned
Kind of like Crut did when he said do the parallel ones first then the series ones?
 
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