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I googled the above (from your post) and found this 555 circuit.... 555 monostable for rising and falling edge detector...
An emitter follower is not an inverter. Use a common emitter transistor instead.Note that VOUT is a negative pulse (with a little bit of overshoot). To change that to a positive pulse, add an NPN emitter follower circuit to the output.
Beg to differ, ag:An emitter follower is not an inverter. Use a common emitter transistor instead.
??Beg to differ,
.. A good example of blindly accepting a simulation result that makes no sense.
Thank you both. And I mean it.cowboybob
Your voltage source on the transistor base is 'upside down', which is causing the inversion you show.