Hello,
We are using a high voltage linear regulator as in the attached mains connected schematic. Its an LR8 linear regulator.
We simply wanted to know how much current was being drawn from its output by our circuit….nothing more.
Therefore we simply noted the depth of the voltage trough at its input rail. As you know, if the input capacitance is known, it is then possible to derive the current drawn from the linear regulator simply by doing this. The voltage trough went down to 134V, and since the input capacitance was 2 paralleled 100nF ceramic capacitors (C1210C104KBRACTU), this means that the current drawn from the linear regulator is 7mA…..
…..However, it turns out that this is not the case. The current being drawn is actually only 3mA. (we found this out by later measuring it directly with a sense resistor)
This must mean that the 100nF capacitors (1210 size) are suffering a loss of capacitance as the voltage rises on them…however, they are 630V rated , X7R ceramic capacitors, and the peak of the voltage on them only goes up to 340V.
So howcome these 630V rated ceramic X7R ceramic capacitors are suffering such severe loss of capacitance?
The 200nF's worth of ceramic capacitance has behaved as if it were only 87nF.
An LTspice simulation of the situation is also shown.
C1210C104KBRACTU 100nF ceramic capacitor datasheet:
www.farnell.com/datasheets/2316000.pdf?_ga=2.58930917.935961512.1522260916-287702491.1506211291&_gac=1.204604068.1521312230.EAIaIQobChMI2Yrg04H02QIVrLDtCh19UwCDEAAYAiAAEgJOTPD_BwE
LR8 linear regulator datasheet:
https://www.google.co.uk/search?sou...1j46i131k1j0i10k1j0i22i10i30k1.80.08upV730r1Q
We are using a high voltage linear regulator as in the attached mains connected schematic. Its an LR8 linear regulator.
We simply wanted to know how much current was being drawn from its output by our circuit….nothing more.
Therefore we simply noted the depth of the voltage trough at its input rail. As you know, if the input capacitance is known, it is then possible to derive the current drawn from the linear regulator simply by doing this. The voltage trough went down to 134V, and since the input capacitance was 2 paralleled 100nF ceramic capacitors (C1210C104KBRACTU), this means that the current drawn from the linear regulator is 7mA…..
…..However, it turns out that this is not the case. The current being drawn is actually only 3mA. (we found this out by later measuring it directly with a sense resistor)
This must mean that the 100nF capacitors (1210 size) are suffering a loss of capacitance as the voltage rises on them…however, they are 630V rated , X7R ceramic capacitors, and the peak of the voltage on them only goes up to 340V.
So howcome these 630V rated ceramic X7R ceramic capacitors are suffering such severe loss of capacitance?
The 200nF's worth of ceramic capacitance has behaved as if it were only 87nF.
An LTspice simulation of the situation is also shown.
C1210C104KBRACTU 100nF ceramic capacitor datasheet:
www.farnell.com/datasheets/2316000.pdf?_ga=2.58930917.935961512.1522260916-287702491.1506211291&_gac=1.204604068.1521312230.EAIaIQobChMI2Yrg04H02QIVrLDtCh19UwCDEAAYAiAAEgJOTPD_BwE
LR8 linear regulator datasheet:
https://www.google.co.uk/search?sou...1j46i131k1j0i10k1j0i22i10i30k1.80.08upV730r1Q