As to the last sentence, you don't magically generate photons of any possible wavelength just because, if that is what you were saying.
THanks, I did drop those exponents didn't I, thought those numbers looked small!
Also i realize that its more than magic, but in a example of my vacuum chamber, I was told that xrays are produced when there is sufficient bombardment against a metal, where i am getting x amount of light in a oxygen/nitrogen environment with copper electrodes, is a small percentage of that going to be xray then? (do i need to worry about exposure to myself?)
Also is my thinking right then , can i apply this equation to electrolysis of water, ie if I need 5.7eV then that works out to
5.7 = 550Kilo Joules per mol
so for 1 mol of water i need to dump 550 kj in to it
550kj is 152 watt*hour or 0.152kW*hour or 9120 watt Minute
so running at 9kw i will only produces a mol which is only 18 gram of water broken down per minute?
But my power bar only provides about 1800 watts , so using that it will actually take 5minute for said 18grams,
Also going by this:
https://www.carstuffshow.com/blog/how-to-convert-gasoline-energy-to-kilowatt-hours-kwh/
gasoline =
33.7 kWh per gallon, = which will only get me about 30 miles
so 33.7kWh/.152kWh = 221 * 5min = 1108 minutes running electrolysis at 1800watts ,it would take to fill my car to the equivalent to a gallon of gas which is:
= 18hrs of electrolysis @1800watts= per gallon of gas
or
= 18hrs of electrolysis @1800watts per 30miles
now i see why water cars dont work!
and that is before factoring in efficiency losses
Also if the resistance of Pure water is 15 Mohm.cm then with 1 cm between my electrodes i will need:
1800watts = v^2 /r 33.7 kWh
= root(1800w*10,000,000ohm)
= 134 kv ??
or with 1mm electrode spacing =
= root(1800w * 1,000,000ohm)
=42kv & 43mA of current
am i still on the right track?