Hi spec,
If "C" is a smoothing capacitor it can't work when both switches are closed as there will be AC across it. An alternative to a capacitor across the relay coils would be a diode across them (For R1 the cathode to the bottom end of the coil.) The coils would probably have enough inductance to maintain the current via the added diode during the unpowered half cycle.
Thanks everyone for your help on this, you have to love the internet, I honestly don't know where else I could get this kind of information so easily, so thanks again
Hi spec, If "C" is a smoothing capacitor it can't work when both switches are closed as there will be AC across it. An alternative to a capacitor across the relay coils would be a diode across them (For R1 the cathode to the bottom end of the coil.) The coils would probably have enough inductance to maintain the current via the added diode during the unpowered half cycle. Les.
Thanks everyone for your help on this, you have to love the internet, I honestly don't know where else I could get this kind of information so easily, so thanks again
I have found some relays that have a coil rated at 240 V AC or DC This is the link to them at CPC
This is a link to the information on them. The coil rating is on page 121. I think two of these relays should do what you want.
I have found some relays that have a coil rated at 240 V AC or DC This is the link to them at CPC
This is a link to the information on them. The coil rating is on page 121. I think two of these relays should do what you want. Les.
I have found some relays that have a coil rated at 240 V AC or DC This is the link to them at CPC
This is a link to the information on them. The coil rating is on page 121. I think two of these relays should do what you want.
I have had some more thoughts about this relay. I have never seen a relay before that is rated for both AC and DC so I was wondering if this is just a DC relay with a bridge rectifier built into it. Also calculating the value of a smoothing capacitor would not just calculating the value so it did not discharge much over half a cycle. The capacitor would charge to near the peak voltage of the mains supply. (240 x 1.414 = 340 volts) Some allowance would have to be made to the value to allow for this.