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So there will not be any damage to the current sources?
So there will not be any damage to the current sources?
Your teacher appears a bit looped. There is no ground loop and your connection will cause no damage to the current sources.
Sooo.. just to be sure (because i'm new to this).
If i connect the black wire (the minus one) from current source 1 to the black wire of current source 2.
The red wire of CS1 to the input of R1 and the red wire of CS2 to the input of R2
Then connect the output of R1 to the output of R2 and then to the black wire of any of the current sources?
The first two steps are fine. That is all your diagram showed. The voltmeter you showed in the diagram by definition is a very high impedance device, so draws no current.
I don't understand this at all? This was not part of your original diagram?
You second diagram is just an upside down version of your first. It is topologically the same as what I simulated.