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That's a good definition of saturation.Saturation = b-e voltage > c-e voltage. . .?
Yes, meaning that the collector-base junction is forward-biased.Saturation = b-e voltage > c-e voltage. . .?
why dont you start a new post?
a lot of discussion and none related to my question..
In order the make transistor fully on, there must be 0V across the collector, this condition is called saturation. (from the book I read)
what is fully on?
The literal interpretation of what you've said doesn't make any sense.what if there is 5V accross the collector?
Tq.
Saturation = b-e voltage > c-e voltage. . .?
I suggest you read the answers they have given to your question.
Most have answered the question correctly.
Its important to realise that in most transistor amplifiers/switching circuits there is a load in the collector between the voltage supply rail and the collector.
If the current flowing thru this load is high enough ALL the supply voltage will be dropped across the load, so the collector voltage will be close to 0V.
Does that help.
EDIT: added a dwg