the program is not runing in C

Nigel Goodwin

Super Moderator

Most Helpful Member

• Nov 1, 2022

• #2

What are you running it on?, and what is printf set to print to?.

 

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Ian Rogers

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• Nov 1, 2022

• #3

ditto... If you are using a PC which compiler are you using

 

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danadak

Well-Known Member

Most Helpful Member

• Nov 1, 2022

• #4

I get a compile error, on the quotation marks surrounding the %d\n,
says they are non ascii characters, so I replaced by double quote marks,
and it compiled and ran.

Code:

printf("%d",r);

Regards, Dana.

 

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Nigel Goodwin

Super Moderator

Most Helpful Member

• Nov 1, 2022

• #5

Just tried it - doesn't work - but simple error:

Fixed:

C:

#include <stdio.h>

int multiplication(int a,int b)
{
    int c;
    c=a*b;
    return c;
}

void main(void)
{
    int r;
    r = multiplication(2,8);
    printf("%d",r);
}

Wrong punctuation marks around %D in printf.

You can try it on-line at:

W3Schools online C editor

The W3Schools online code editor allows you to edit code and view the result in your browser

www.w3schools.com

 

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Ian Rogers

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• Nov 1, 2022

• #6

I don't... The syntax seems to be fine..

 

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S

sxy

Member

• Nov 1, 2022

• #7

#include <stdio.h>
int multiplication(int a,int b)
{
int c;
c=a*b;
return c;
}
void main(void)
{
int r;
r = multiplication(2,8);
printf(“%d”,r);
}

 

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Ian Rogers

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• Nov 1, 2022

• #8

OMG I typed it all in... Where did those inverted commas come from..

 

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S

sxy

Member

• Nov 1, 2022

• #9

So what was the problem in my code?

 

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Ian Rogers

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• Nov 1, 2022

• #10

some text editors actually invert the comma, but in C they are the same character

The extended ones will not work..

 

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Nigel Goodwin

Super Moderator

Most Helpful Member

• Nov 1, 2022

• #11

sxy said:

So what was the problem in my code?

Click to expand...

I explained in post #5, you had : “%d” it should be "%d" - wrong punctuation marks.

 

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Nigel Goodwin

Super Moderator

Most Helpful Member

• Nov 1, 2022

• #12

Ian Rogers said:

OMG I typed it all in... Where did those inverted commas come from..

Click to expand...

Bad mistake typing it in, I cut and pasted

 

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S

sxy

Member

• Nov 1, 2022

• #13

#include <stdio.h>
int main() {
//array declaration
int rollNo[10];

//taking inputs
for(int i=0;i<10;i++)
scanf("%d",&rollNo);

//printing
for(int i=0;i<10;i++)
printf("%d ",rollNo);
return 0;
}
the program, is not runing.
It should take 10 integers from the user and then print them again.

 

Last edited: Nov 1, 2022

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danadak

Well-Known Member

Most Helpful Member

• Nov 1, 2022

• #14

Here is your error :



You did not specify the specific array element to print.

Is your compiler not showing you error dialog ?


Regards, Dana.

 

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Ian Rogers

User Extraordinaire

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Most Helpful Member

• Nov 1, 2022

• #15

scanf() wants a keyboard input....
char input[3];
for(int i=0;i<10;i++)
{
scanf("%c",input) ;
rollNo[1] = atoi(input);
}

Scanf() does not work on that web site??

 

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Ian Rogers

User Extraordinaire

Forum Supporter

Most Helpful Member

• Nov 1, 2022

• #16

Try this one

Online C Compiler - online editor

OnlineGDB is online IDE with c compiler. Quick and easy way to compile c program online. It supports gcc compiler for c.

www.onlinegdb.com

Scanf works here..

Code:

#include <stdio.h>
#include <stdlib.h>
int main() {
//array declaration
int rollNo[10];
char inpt[3];

//taking inputs
for(int i=0;i<10;i++)
    {
    scanf("%s",inpt);
    rollNo = atoi(inpt);
    }
//printing
for(int i=0;i<10;i++)
printf("%d ",rollNo);
return 0;
}

 

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danadak

Well-Known Member

Most Helpful Member

• Nov 1, 2022

• #17

Should this :

Code:

for(int i=0;i<10;i++)
    {
    scanf("%s",inpt);
    rollNo = atoi(inpt);
    }

be this :

Code:

for(int i=0;i<10;i++)
    {
    scanf("%s",inpt);
    rollNo[i] = atoi(inpt);
    }

Also do same for rollNo in print statement, eg use as array element....


Regards, Dana.

 

Last edited: Nov 1, 2022

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danadak

Well-Known Member

Most Helpful Member

• Nov 1, 2022

• #18

This ran :



Regards, Dana.

 

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T

tepalia02

Active Member

• Nov 1, 2022

• #19

It should be like this
#include <stdio.h>
int multiplication(int a,int b)
{
int c;
c=a*b;
return c;
}
void main(void)
{
int r;
r = multiplication(2,8);
printf("%d",r);
}

Please note that your “%d” looks different than mine. The online C compiler found this error when I copy pasted your code.

 

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Nigel Goodwin

Super Moderator

Most Helpful Member

• Nov 1, 2022

• #20

tepalia02 said:

It should be like this
#include <stdio.h>
int multiplication(int a,int b)
{
int c;
c=a*b;
return c;
}
void main(void)
{
int r;
r = multiplication(2,8);
printf("%d",r);
}

Please note that your “%d” looks different than mine. The online C compiler found this error when I copy pasted your code.

Click to expand...

Perhaps you should try reading the thread?, that answer has long since been given - more than once!.

 

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