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That circuit doesn't stop th motor, it just outputs a signal when the current limit is exceeded.
The transistor starts to turn on when the base emitter voltage exceeds about 0.6V to 0.7V so the current limit can be calculated using Ohm's law, 0.6/0.8 = 0.75R.
If you want to shut down the motor, you'll need to have a time delay.
Why not just use a polyfuse as I said in my response on the last page?
I know it isn't the done thing, but you'll need to select a polyswitch with a trip current of about 80% of the desired value, otherwise it's possible it'll never trip.
Sorry to tell you but your confusion about units and your questions make to suspect that you are lazy (sure you have the right to it..) or you did not play enough with calculations to not finding your mistakes before posting.
Sorry to tell you but your confusion about units and your questions make to suspect that you are lazy (sure you have the right to it..) or you did not play enough with calculations to not finding your mistakes before posting.
men, I fooled myself to post the values .. the power of my engine is between 600mA to 800mA, to me what interests me is that I get a current limiter .. I already immunotherapy in google, in schemes against anything, pa limit of my current motor and to stop when it exceeds the current!
Mike gave you a circuit to do exactly what you want to do. His last circuit listed the shunt resistor values and gave you a choice. You use the Out of the transistor to do whatever you want when the current reaches the trip limit. What else can be done?
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