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Resistor Circle

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mpaap

New Member
link - I need help with that homework!
Check out the picture. Is there anyone who can solve it? or is there a program which solves it?

Calculate the impedance circuit is shown in the figure, the current in all resistors and resistors abeyance annually. All resistors have resistance 10oomi scheme of the limbs and voltage 44V [translated by google translator]

Supply Voltage = 44V
each resistor = 10Ω

and in Estonia It's I=U/R, not I=V/R

I know:
I,U,R, R1,R2,R3,R4,R5,R6, I1,I2,U1,U2
i need to know:
I3,I4,I5,I6,U3,U4,U5,U6

Waiting for assist, thanks
 

Chippie

Member
I'm not going to give you the answer....but here's a little help...I've simplified the drawing but there's a little work left for you to do...
 

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mpaap

New Member
hmm, i'll try
Thanks for your help.

I don't get it, how do i find from your simplified circuit a I3 or I4 or I5 or I6 ?
 
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Chippie

Member
here's a clue....read up on resistor networks...resistors in series and parallel....
 

mpaap

New Member
i do not know what to do next :/
i found all the resistors resistivity
R123456 = 11Ω
and I = 4A
What can i find next?
 

Chippie

Member
You need to show how you arrived at your figures....

Show us your calculations.......
 

birdman0_o

Active Member
How did you end up with 11ohms if it is initially given as 10?

The equations you will need : V = IR
Facts: In parallel 1/R1 + 1/R2....1/Rn = 1/Rot
In series R1 + R2 ... + Rn = Rtot
 

Willbe

New Member
I get 15 ohms in parallel with 10 and that combo in series with 5.
 

Chippie

Member
ok, the combined resistance of the 5r and the two parallel ones(10 and 15) comes out at 11 ohms...
With a pd of 44 volts across the 2 resistors which are effectiviely in series, gives a current flow of 4 amps...

Calc the voltage across the first two 10 ohm resistors by V=IR...then subtract that from the 44v to give the voltage across the remaining three....

Now are we getting somewhere?
 

ericgibbs

Well-Known Member
Most Helpful Member
and maybe you can suggest me something
hi,
Lets try it in simple steps.:)
You know that all the resistors are 10 ohms.

Step1:
So what is the resistance of R4 and R5 in parallel..???

Answer this first.:)
 

mpaap

New Member
Resistance of R4 and R5 is 5 ohms, same with R1 and R2. i calculated whole resistance, and it's 11 ohms
 

mpaap

New Member
well, if the voltage is 44 and resistance is 11 then I = V / R so.. I = 44 / 11 = 4A
now what?
 

ericgibbs

Well-Known Member
Most Helpful Member
well, if the voltage is 44 and resistance is 11 then I = V / R so.. I = 44 / 11 = 4A
now what?
Good.

You know the value of R1 and R2 in parallel is 5R, so use ohms law to find the voltage drop across R1 and R2

Vdrop= 5ohms * 4Amps =.......
 
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