resistance question

robotgangsta

New Member

• Feb 26, 2006

• #1

if i have 10 10k resistors in a series and a 50k resistor is placed parrallel across them all what will be the overall resistance and can you explain in detail what you do to get the answer

 

robotgangsta

New Member

• Feb 26, 2006

• #2

anyone know

 

eblc1388

Active Member

• Feb 26, 2006

• #3

Oh man!!

Can't you just work out 100K in parallel with 50K?

 

Dr.EM

New Member

• Feb 26, 2006

• #4

1/R total = 1/R1 + 1/R2 etc for resistors in parallel. The 10 10k in series make 100k as was pointed out. I usually check with a multimeter aswell.

 

akg

New Member

• Feb 27, 2006

• #5

robotgangsta said:

if i have 10 10k resistors in a series and a 50k resistor is placed parrallel across them all what will be the overall resistance and can you explain in detail what you do to get the answer

Click to expand...

(10*10K) || 50K -> 33.3K

 

W

Wrighty

New Member

• Mar 2, 2006

• #6

yea thats bang on, the total resistance for resistors in parallel will always be just less that the smallest leg of that parralel arrangement.

 

lord loh.

Member

• Mar 2, 2006

• #7

Was this a quiz???

 

L

ljcox

Well-Known Member

• Mar 2, 2006

• #8

The easy way to do it is to realise that 50k = 100k/2, so 50||100 = 100/3 = 33.333k