rectifier capacitance value

I'm using a single shunt capacitor as a filter cap out of a centre tapped bridge rectifier. Assuming I want a ripple voltage of 1V, i used the following formula which is a derivation from Q=CV, Q=It and t=1/f

Capacitance = (Load Current ) / (Ripple Voltage * Frequency)

Would this derivation be correct?

Not quite. The ripple period t = 1/2f because you are using a full-wave rectifier, where the ripple frequency is 100Hz or 120Hz.

oh yeah sorry! i forgot to add the note that the frequency is 100Hz becaue in my area the supply is at 50Hz..thanks for verifying!