None.Here's an important question that I can't figure out.

What king of amperage can I expect to see after the 115 vac 15 amp current runs through a 370v 80uF Run Capacitor, then converts to vdc through a 500v rated Bridge Rectifier?

A capacitor has an impedance that varies with the frequency of the signal going through it. At 60 Hz, an 80 uF capacitor has an impedance of 33 ohms. For simplicity's sake, lets replace the capacitor in your with a 33 ohm resistor as run the numbers.

Using Ohm's law, the voltage developed across a 33 ohm resistor with 15 A going through it is 495 V. This means that to get 15 A through the resistor, the voltage source must be 495 V. And that's just for the resistor. If you want 300 V across the batteries in series with the resistor, then the total is 795 V for the circuit.

Also, a bridge rectifier cannot "convert" a low input voltage to a high output voltage.

The circuit in post #8 is a half-wave voltage doubler. The peak output voltage is approx 2.8 times the input RMS voltage, so for 115 Vac in that is approx. 325 Vpp (volts peak to peak). Note that as soon as you draw any current, that peak voltage will have a lot of 60 Hz ripple; the effective value of the DC output voltage will decrease. With only 80 uF capacitors, it will take less than 0.5 A of output current to have the ripple approach 50% of the peak value. I'm running these numbers in my head, so they might be off a bit. But you get the idea.

ak