A single red or green pilot LED requires only an 56K resistor across 230V. Normal LEDs have low brightness otherwise a bright type must be used. A diode resistance combination can be used for getting good brightness. Here resistance must be atleast 2W type.
Which would be great if we were discussing pilot lights.
We were discussing large quantities of junk LEDs run of the line. My point is that you can pay $50 to get "junk" whites to put out 500Lm for 20W or you can pay $25 to get lighting class LEDs to put out 500Lm for 5W.
I want to derive power supply for 270 LED's ( 1 rows of 10 LED's in series - Each LED 3.6v DC ). How to derive the circuit ? Any Idea ? Without transformers.
read the thread.... driving LEDs off the mains like that is inefficient in power and build time...as well as being prone to failure in long term service.
a little more power supply complexity gets a lot more light out of a only a few lighting class LEDs
why using a transformer just see how chritmas led light are made, they are no transformer, no extra parts at all, just leds in series and maybe a capacitor or resistor. i would do it very easily, one bridge rectifer and one resistor per branch of led.
why using a transformer just see how chritmas led light are made, they are no transformer, no extra parts at all, just leds in series and maybe a capacitor or resistor. i would do it very easily, one bridge rectifer and one resistor per branch of led.
Here is the basic schematic of the circuits I have been building and have had several of them running continuously now for about 6 -7 years now.
You will have to calculate the voltages and values for the two capacitors and R1 can be any where from 100 to 1K ohms.