PnP Transitor Base Voltage Value?

Hello,

Given this circuit that is attached, I'm assume with the voltage divider law, the votlage to the base of the transistor should be 2V, but when simulating it, it shows 2.4V. What causing the value to be non-ideal?

Thanks.

The base of Q1 takes to work. The current gain of Q1 appears to be about 136. The emitter resistance is 220 ohms. The base resistance is 136 x 220= 30k ohms.
The voltage at the base is about 2.5V
For 2.5V to happen you need R2=10k and (R1 parallel with the base resistance of Q1)=10k.
Think of Q1 looking like a 30k resistor from base to (+5v).

These are approximate values.

Simple answer.
The current flowing from the base to the emitter is pulling the base voltage positive.