RoboWanabe
Member
I have an IC which i need help configuring.
I am concerned with the two pins DI ( Driver in) and DE (Driver enable)
for both pins it says the Input high voltage must be MIN= VCC-0.4. And Input low voltage max= 0.4v. I belive i must also supply a 20ma current to the pins, this activates a optocoupler diode.
I am driving both pins from a micro whos max pin voltage is 3.3v with a max output current of 20ma.
Can some one please help me with the calculations for a resistor connecting the pins together.
View attachment 68751
I hope i've included everything you need. I do know its simple ohms law whihc i can do but i just struggle biasing a circuit the way i need it, but i've just started a new job and i am learning alot
I am concerned with the two pins DI ( Driver in) and DE (Driver enable)
for both pins it says the Input high voltage must be MIN= VCC-0.4. And Input low voltage max= 0.4v. I belive i must also supply a 20ma current to the pins, this activates a optocoupler diode.
I am driving both pins from a micro whos max pin voltage is 3.3v with a max output current of 20ma.
Can some one please help me with the calculations for a resistor connecting the pins together.
View attachment 68751
I hope i've included everything you need. I do know its simple ohms law whihc i can do but i just struggle biasing a circuit the way i need it, but i've just started a new job and i am learning alot