Futterama
Member
Hello forum,
I'm interfacing a 40pin PIC with a 3½digit LCD display. The LCD is a "clean" LCD - there is no IC onboard. It's the same type of display you would find in any cheap multimeter, the difference is, this LCD has pins to solder.
I need to know how the "signal" to the individual LCD segments should be shaped to give the best viewable result.
I measured on an old multimeter display with my scope, and found that the signal for the LCD segments was a square wave at 50Hz.
Now, the supply voltage for my LCD is stated to be 3.0V. If I supply the LCD segments with a square wave at 50Hz and 3V, the LCD segment is barely visible. If I crank the voltage up to 5V, the LCD segment is clearly visible.
But, I'm not sure if 5V is a good idea since the datasheet says 3.0V. But perhaps it's 3.0V average? With a 50% duty square wave, that would give me a Peak-to-Peak voltage of 6V.
What is your opinion on this? Do you perhaps know how the "signal" from a true LCD driver looks like?
Thanks.
Regards,
Futterama
I'm interfacing a 40pin PIC with a 3½digit LCD display. The LCD is a "clean" LCD - there is no IC onboard. It's the same type of display you would find in any cheap multimeter, the difference is, this LCD has pins to solder.
I need to know how the "signal" to the individual LCD segments should be shaped to give the best viewable result.
I measured on an old multimeter display with my scope, and found that the signal for the LCD segments was a square wave at 50Hz.
Now, the supply voltage for my LCD is stated to be 3.0V. If I supply the LCD segments with a square wave at 50Hz and 3V, the LCD segment is barely visible. If I crank the voltage up to 5V, the LCD segment is clearly visible.
But, I'm not sure if 5V is a good idea since the datasheet says 3.0V. But perhaps it's 3.0V average? With a 50% duty square wave, that would give me a Peak-to-Peak voltage of 6V.
What is your opinion on this? Do you perhaps know how the "signal" from a true LCD driver looks like?
Thanks.
Regards,
Futterama