# Need Help figuring two things out??? ASAP

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#### Ravi

##### Member
Here is an easy formula. In the first case, caps are connected in parallel. The effective capacitance of the network is simply equal to the sum of the individual capacitances.Hence, C=0.1+0.2+0.3

In the second case, resistors are in parallel. Hence the reciprocal of the effective resistance of the combination is equal to the sum of the reciprocals of the individual resistances. Therefore, 1/R= 1/100+1/100+1/100+1/100

thanks man

#### BuzzKill

##### New Member
so the second is 400 ohms or is it 25 ohms?

#### Ravi

##### Member
It is 25 Ohms. However,if there are only two resistors connected in parallel the formula could be re-arranged as:

R=R1XR2/R1+R2 that is, product of individual resistance divided by sum of individual resistance.

In general whenever two resistors of identical value are wired in parallel, the resistance of the combination will be equal to half that of each individual resistor, whilst the power rating of the combinations will be double that of each individual component.

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