Here is an easy formula. In the first case, caps are connected in parallel. The effective capacitance of the network is simply equal to the sum of the individual capacitances.Hence, C=0.1+0.2+0.3
In the second case, resistors are in parallel. Hence the reciprocal of the effective resistance of the combination is equal to the sum of the reciprocals of the individual resistances. Therefore, 1/R= 1/100+1/100+1/100+1/100