Microphone circuit

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can i make mobile charger using my idea of circuit of electret microphone ???sound pulses coming from any instrument will get converted into electrical signal...as mobile charger requires 5-6 V DC supply...(pls correct me if i'm wrong...as i told in my 1st post,i'm beginner student of electronics...)
 
ok my last query:in my attached document, by varying R1,R2 can i obtain required output???in given circuit graph,it is giving high and almost same gain between 100Hz-50KHz...(human hearing range;20 Hz-20KHz)

**broken link removed**
 
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nnb29 said:
ok my last query:in my attached document, by varying R1,R2 can i obtain required output???in given circuit graph,it is giving high and almost same gain between 100Hz-50KHz...(human hearing range;20 Hz-20KHz)
Click to expand...

Varying them will change the gain - but it really depends what your 'required output' is.
 
The battery needs a DC current to charge it.
But the output of the mic preamp is an AC signal with its current too low.

Instead of rectifying and boosting the output current of the mic preamp then simply use the preamp's power supply to charge the other battery.
 
Can u pls tell me in details what u want to say???
 
Maybe he wants the preamp to charge the battery for the preamp. Impossible.
 
after doing some improvement in my attached circuit...is it possible what i want to do????if yes pls suggest modifications...
 
A microphone preamp circuit is completely different to a battery charger circuit.
 
nnb29 said:
after doing some improvement in my attached circuit...is it possible what i want to do????if yes pls suggest modifications...
Click to expand...

In a word "no". How long did you plan on yelling into the mike? If the idea was practical they would have built it into phones.
 
nnb29 said:
**broken link removed**
i want 5-6 dc volt to charge battery....is it possible to obtain by varying R1 and R2 in my attachment???
Click to expand...

Do you want to use this 9 V -powered microphone amplifier circuit to source a "voltage" of 5-6 VDC? I presume this "9V" you power the circuit comes from a 9V battery?


Whatever... I understand you believe it is what you need to charge a battery. OK. If so, I'd say replace the lower 47 k resistorwith a 100 K, then remove the 10 uF capacitor. You will then find 5 - 6 V DC on the output.

If I were you, I'd put a piece of tape over the microphone (or better still remove it completely), because any sound wave in the room is going to disrupt the DC output voltage.

Best of luck!
 
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