The led must be the right way round and a resistor to limit the curent tugh the led.Use the Ohoms law to caculator the resistance (3 mA trugh the LED sod do)
They tested it at 3.5V, 10mA. This means that we want that across it. Let's assume a 14V power supply coming in.
Vresistor = 14V - 3.5V = 10.5V dropped across the resistor
R = Vresistor / I
I = 10mA from above
R = 10.5/10mA = 1.05kohm
you would just need to hook this up in series, and you'd be good to go.
Edit: Another thing I thought I'd mention. In this configuration, the resistor would be dissipating I^2*R =~ 0.1W. A 1/4 watt resistor would be satisfactory. If you were to use an LED with more current, you might have to step it up to a 1/2 watt resistor.