I have never really done this form of electronics math but do want to learn... am a software engineer by trade and haven't delved into hardware too much.Do you know how to calculate resistor dividers to get a lower reference voltage from a higher voltage like 5v?
The 555 I refer to is th e cut-off circuit that already exists on the lower half of the diagram to force the enable pin high if there is no incoming data.No 555's required.
Currently the system takes around 500mA per train on the track (but this varies depending on brand/headlights/etc...)I need to know what the normal current draw is for whatever you are powering first.
You might not believe it, but that's the way I actually wired it up, as opposed to drew itThat section needs to have pin 5 and 4 swapped.
2 0.27Ohm/5Watt resistors did the trick!You might try paralleling some 0.47 ohm resistors (or whatever you have on hand) to beef up the current trip point.
Another typo on my diagram, it is indeed 1uf.BTW, with that 10uf cap instead of 1uf you might get more like 10 seconds...
I've just been playing with this tonight.. and it works great....you can connect an LED to a 2.2k resistor to +5v (anode toward +5v) and connect that resistor to the output of another inverter...
this was occuring, but the parallel 0.27ohms seemed to drop the resistance sufficiently?There is also the possibility that when the train starts up the surge current trips the current sense. We'll have to deal with that too if that happens.
0.27 Ohm / 5 WattWhat power rating are your sense resistors?
No problem there, the rest of the circuit is assumed to be OK.. which, although dangerous, is a choice I'm willing to make.MrAl said:Please note however that i did not verify the entire circuit...
Last item on the agenda is to bridge the outputs on the L298, or at least use the second one as well.MrAl said:I think you will soon be done with this thing...
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