Looks like a reasonable waveform, but not knowing what the signal should look like I cant really comment.codan said:I have hooked up a circuit to read the frequency of the pulses to test things out, after much playing around i have what seems to be a good reading on the Monitor?
Not really, see my comments further down the page.codan said:Is this ok for a reading of the frequency of a circuit?
There are 1,000,000 uS in one second and 1,000mS in one second.codan said:The time readings are a bit hard to read on the bottom but from left to right read:
0s 163.80us 327.60us 491.40us 655.20us 819.00us 982.80us 1.15ms 1.31ms 1.47ms 1.64ms.
I am not sure how to work out the frequency of this circuit or how many us or ms in a second etc--AARRGGGHHH!!
At a quick look, there seems to be narrow pulses and wide pulses, again not knowing the source of the signal, it is difficult to say, but it looks like a form of Pulse Width Modulated signal.codan said:The pulses vary so what do you call this type of Signal?
Not necessarily interference, as in an unwanted external signal. It could be that the voltage is varying a little bit, or there is some noise on the signal.codan said:Also on the reading on the Horizontal lines --just below centre--some are a little fuzzy, is this just some sort of electrical interference?
codan said:Ok, i'll give it a shot:
It takes 819.00us to complete one cycle, that is .000819sec
So if i get 1 divided by .000819= 1221 Hz
Is this correct? Or do i have no idea?
codan said:Ok, i'll give it a shot:
It takes 819.00us to complete one cycle, that is .000819sec
So if i get 1 divided by .000819= 1221 Hz
Is this correct? Or do i have no idea?
codan said:Thanks to all who replied, i get what your saying about the complex nature of the signal the the Frequencies with the Frequency so to speak. All very interesting!
One thing though, i thought it was a square wave, can i have this set incorrectly showing some other waveform as a square wave?
I have run it on the transient function & every setting imaginable & all i get is a square waveform?
The signal is coming from an old Metal Detector of mine.
Torben said:If that's because I said it looks kind of like a square wave, that's just because the waveform is square-ish. It's certainly not a sine or triangle or sawtooth, for instance. I think the definition of a true square wave is that it is regular--i.e. it goes instantly from low to high, stays there for some length of time, then drops instantly from high to low, stays there for the same length of time, and repeats. I wouldn't call this a true square wave, but I could be wrong about that.
Torben
ericgibbs said:I would suggest the OP inputs a variable amplitude sine wave from a generator in order to check it out.
codan said:Please advise?
hi,codan said:I can setup something simmilar if i have this correct.
I have a stepdown 240v AC to 12V AC transformer that i can connect to the mains via a 10amp Variac that should produce a low voltage sine wave--if i have this correct.
Do you mean input a sine wave into the O-scope to check it is functioning correctly?
Thank for your input on things, it is very helpful.
hi,codan said:Might be better if i attach the image to give an idea, i'll get started.
ericgibbs said:hi,
Using a Variac with a step down isolated transformer would be a simple check.
Use a voltmeter to check the rms value of the sinewave, allow a peak sine amplitude of Vrms * 1.4 eg: if your voltmeter reads 1Vac then the sinewave on the PC should appear as a 2.8V peak to peak waveform. OK.
Do you follow.?
codan said:Hi,
That was the before picture, you don't want to see the after shot!
I set it up & fumbled around on the O-scope & have attached the results.
It's a bit out of focus again, left hand verticle column is in 5.0V increments & time left to right is in 5ms steps.
I set the input voltage at 6.0v with the multimeter so do i multiply this by 1.4 to get peak values, the scope is at 8.4v?
Thought there may have been a typing error on the previous post?
For the time settings i went 1 divided by 50Hz= .02/sec = 20ms if i have it right, it seems to be ok on the O-scope.
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