Help with explaining circuit

[TsAmE]

I am really confused by this question and dont know what to draw. Could someone please post the diagram (using paint etc) and explain it to me? Thanks

1a) In a toy crane, a simple switch connects a small motor to a 6V battery. However,
when the switch is turned ON the motor starts with a jerk, running at full speed almost
immediately. When the (two-way) switch is turned to the STOP position the motor is
short-circuited and stops immediately.

To make the toy crane more realistic, you are asked to design a circuit using the same switch,
but adding a resistor R, capacitor C and Darlington emitter follower, so that when the switch
is turned ON the capacitor charges gradually through R (say over a second or two) and the emitter follower applies this steadily rising voltage to the motor. Thus the motor does not start with a jerk, but
accelerates smoothly up to its running speed.

Similarly, when the switch is turned off the capacitor gradually discharges into R. As a result the motor does not stop suddenly, but slows down and comes to a gentle stop. Choose R and C so that the ‘time-constant’ t = RC is about a second. Draw a circuit diagram.

 

[Roff]

Do you know what a Darlington is?
Do you know what an emitter follower is?
Tell us what you know about these, and we will try to help.
The homework forum is not here to give you answers on a silver platter. You have to do some work.

 

[TsAmE]

The thing is that I dont understand how these parts work, which is why I am having trouble doing it, could you please explain them?

 

[Hero999]

Have you tried Googling them first?

What about a mechanical solution?

Connecting a flywheel directly to the motor's shaft will make it speed up and slow down more gradually.

Not shorting the motor's terminals will greatly increase the slowdown time.

 

[Roff]

Have you tried Googling them first?

What about a mechanical solution?

Connecting a flywheel directly to the motor's shaft will make it speed up and slow down more gradually.

Not shorting the motor's terminals will greatly increase the slowdown time.

But that doesn't fit into the definition of the problem.

 

[Hero999]

How does it not solve the problem?

He wants the motor to start and stop gradually. It might not have to be an electrical solution.

 

[Roff]

Here's a quote from the OP:

you are asked to design a circuit using the same switch,
but adding a resistor R, capacitor C and Darlington emitter follower, so that when the switch
is turned ON the capacitor charges gradually through R (say over a second or two) and the emitter follower applies this steadily rising voltage to the motor.