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i want to store 1bit flag, so i built this.
clock is always runnig as shown , input arrives in pulse so output becomes high.
but when input is zero , it output remains high
ok it is running but , current through R3 AND LED is 3.6mA, if i am not wrong it should, I=V/R which is 9mA.
and also output voltage of Q is 5V, but in datasheet it is shown Min. 9.95V at Vdd-10V
ok silly mistake by me.
now current is comming 7.5mA acrross R3 , does LED also have resistance which is to be considered ?
Also when i change value of R3 voltage value at Q output pin changes.
it decreases with decreasing resistance value.
when R=10ohms Q=6.8V
when R=100ohms Q=8.8V
when R=1000ohms Q=9V
hey man , i replaced it with LED, i downloaded and checked this it shows LED in it :?hi,
You are still using a diode as an LED, that diode has only a forward voltage drop of 0.7V, use a RED LED, which is ~2V forward drop. [your current results will be misleading with a diode]
so what this has got to do with falling voltage. the load is controlling voltage drop accross Q and gnd ? , what if i connect many transistors with load like that in parallel or sereis with output Q, then load will change and it will change all voltage drop accross output !The falling voltage, when the current load is increased, is the point I was making yesterday in your 4013 thread, you will not get 15mA at 15V.
> Without using transistor the output voltage at Q has fallen from 8.9V to 2.9V and current has fallen from 73mA to 22mA.
if i consider Q as voltage source , this all things seem absurd, breaking the rules. what should i consider Q ?
But i am not interested in keeping voltage at highest , i am interested in keeping it constant. like Q should act as voltage source. as battery
what is Vo in conditions ?
and what is the resistance of LED because current through R3 (1k) is still comming 7.5mA and not 9mA !
its not in my hand to allow voltage drop across Vbe.
Vbe voltage drop will happen naturally in transistor , it is not in my hand i guessAlso are you allowing for the Vbe voltage drop across the transistor.?
Vbe voltage drop will happen naturally in transistor , it is not in my hand i guess