:S bare with me if im wrong but do you take the voltage drop so 10v-15v=5v and multiply that by the resistor value then divide it by 4.7, giving us 5..
:S bare with me if im wrong but do you take the voltage drop so 10v-15v=5v and multiply that by the resistor value then divide it by 4.7, giving us 5..
Its important to calculate the Ic current, from that assuming that the current into the base is 'zero', this would mean the same current flowing in the 1.2K resistor is 'virtually' the same as the current thru the 4k7.
However there MUST be a small current Ibase flowing into the base of the transistor other wise no collector current would flow in the 4.7K.
Work out this small Ibase current and add it to the emitter current, let me know what you get
Obviously I am trying to give you clues on how to solve this problem on your own, rather than just giving you the answer.
I know homework question too. But fortunately he will learn something about this. Either one of:
* "I'm stuck but here's what I have got so far"
* "The answers (numbers as stated above) helped me to solve the issues"
This guy actually have two replies to the given suggestions on this forum (as opposed to most other students just don't throw out a copy of their homework and we never hear from them again). Personally I think he dererve some help. Now, If he responds, we get a clue if he got it right or not.